Arrays are sorted in custom order
Eyeza edited in Tue, 23 Aug 2022
let arr1=['早晨','中午','下午','晚上']//排序规则
let arr2=['晚上','下午','中午']
=>['中午','下午','晚上']If you want arr2 to sort according to the rules of Arr1, is there any way
3 Replies
arr2.map(x => ({value: x, index: arr1.indexOf(x)})).sort((a, b) => a.index - b.index).map(x => x.value)
Define a map, morning: 1, noon: 2
Then, the sorting method of array is used to get the sorting order of the current noon in the map, compared with other methods
In Arr1, remove what is not in arr2, it's OK ~ ~ am I very good, like it
arr1.filter(e => arr2.includes(e));
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